Chapter test · Grade 12 · Mathematics
Mathematics Part-I · Ch 5
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40 minutes · 20 questions
The function \(f(x) = |x|\) is:
The derivative of \(\sin(2x)\) with respect to \(x\) is:
If \(y = e^{3x}\), then \(\dfrac{dy}{dx}\) equals:
If \(y = \sin^{-1}\left(2x\sqrt{1-x^{2}}\right)\), then \(\dfrac{dy}{dx}\) equals (for \(|x| < \dfrac{1}{\sqrt{2}}\)):
\(\dfrac{d}{dx}\left(\log(\sin x)\right)\) equals:
If \(f(x) = x^{2}\) and \(g(x) = \sqrt{x}\), then \(\dfrac{d}{dx}(f \circ g)\) at \(x = 4\) is:
If \(y = x^{x}\), then \(\dfrac{dy}{dx}\) equals:
If \(f(x) = \begin{cases} 3x - 2, & \text{if } x \le 1 \\ kx + 5, & \text{if } x > 1 \end{cases}\) is continuous at \(x = 1\), then \(k\) is:
If \(x = a\cos\theta\), \(y = a\sin\theta\), then \(\dfrac{dy}{dx}\) equals:
If \(y = x\cos x\), then \(\dfrac{d^{2}y}{dx^{2}}\) equals:
Assertion (A): The function \(f(x) = x^{2}\sin\left(\dfrac{1}{x}\right)\) for \(x \ne 0\) and \(f(0) = 0\) is differentiable at \(x = 0\).
Reason (R): \(\left|h\sin\dfrac{1}{h}\right| \le |h|\), and the squeeze theorem gives \(\lim_{h \to 0} h\sin\dfrac{1}{h} = 0\), so \(f'(0)\) exists.
Assertion (A): If \(f\) is differentiable at \(x = a\), then \(f\) is continuous at \(x = a\).
Reason (R): Differentiability at \(a\) requires \(\lim_{h \to 0}\dfrac{f(a+h)-f(a)}{h}\) to exist, which in turn forces \(\lim_{x \to a} f(x) = f(a)\).
Assertion (A): The function \(f(x) = |x| + |x-1|\) is continuous everywhere but not differentiable at \(x = 0\) and \(x = 1\).
Reason (R): \(|x-c|\) is continuous everywhere on \(\mathbb{R}\) but not differentiable at \(x = c\) (a corner).
Which statements about derivatives are correct?
Which statements are correct?
Match each function with its derivative:
A particle's position is \(s(t) = t^{3} - 6t^{2} + 9t\) m. Its velocity at \(t = 2\) s is:
A taxi company in Dubai models the fare (in dirhams) for a ride of \(x\) km by \(f(x) = 2x^{2} + 10\) for \(0 \le x \le 4\) and \(f(x) = ax + b\) for \(x > 4\). To make the fare change smoothly at \(x = 4\) (the fare is continuous and has no sudden change in its rate), the value of \(a + b\) is:
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