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Chapter test · Grade 12 · Physics

Wave Optics

Physics Part-II · Ch 2

  • 30 questions
  • 40 minutes
  • 1 mark each
  • Nothing taken off for a wrong answer
40 minutes30 questions
Question 1of 30

In Young's double slit experiment with slit separation \(d\), fringe width \(\beta\) at distance \(D\) for wavelength \(\lambda\) is:

Question 2of 30

In YDSE, slits are illuminated by light of wavelength \(500\ \text{nm}\); slit separation \(0.5\ \text{mm}\); screen distance \(1\ \text{m}\). Fringe width is:

Question 3of 30

The condition for constructive interference in YDSE is path difference equal to:

Question 4of 30

Light of wavelength \(600\ \text{nm}\) in air enters a glass block of refractive index \(1.5\). Inside the glass, its wavelength and frequency are (take \(c = 3 \times 10^{8}\ \text{m s}^{-1}\)):

Question 5of 30

When the slit in a single-slit diffraction experiment is made narrower, the central maximum on the screen:

Question 6of 30

In Young's double slit experiment with \(d = 1\ \text{mm}\), \(D = 1.5\ \text{m}\), the path difference at a point \(1.5\ \text{mm}\) from the centre is:

Question 7of 30

Two sources are coherent if they emit waves of:

Question 8of 30

Two coherent sources of intensity \(I\) each interfere. The maximum intensity at constructive bright fringe is:

Question 9of 30

Huygens' principle is used to explain:

Question 10of 30

Two slits illuminated by \(600\ \text{nm}\) light produce a fringe pattern. If the same slits are illuminated with \(480\ \text{nm}\) light, the fringe width:

Question 11of 30

Assertion (A): Diffraction patterns produced by long-wavelength waves are wider than those produced by short-wavelength waves through the same slit.

Reason (R): Angular width of diffraction patterns is proportional to \(\lambda/a\), so longer-wavelength waves produce broader patterns.

Question 12of 30

Assertion (A): In single-slit diffraction, the central maximum is twice as wide as any of the secondary maxima.

Reason (R): Width of central maximum (between first minima) is \(2\lambda/a\), while the spacing of successive minima around any secondary maximum is \(\lambda/a\).

Question 13of 30

Assertion (A): The colours seen when a CD is viewed in white light are due to diffraction.

Reason (R): Diffraction is a general characteristic exhibited by all types of waves, such as sound waves, light waves, water waves and matter waves.

Question 14of 30

Assertion (A): Coherence between two light sources is essential for stable interference.

Reason (R): For a sustained pattern of bright and dark fringes the relative phase between the sources must remain constant in time.

Question 15of 30
  1. I. Fringe width is given by \(\beta = \lambda D/d\).
  2. II. Bright and dark fringes alternate equidistantly on the screen.
  3. III. The central fringe is bright (zero path difference).

Which of the above are CORRECT for YDSE?

Question 16of 30
  1. I. The central maximum is the widest of all maxima.
  2. II. Minima occur at angles \(\theta \approx n\lambda/a\) for \(n = \pm 1, \pm 2, \pm 3, \ldots\)
  3. III. All secondary maxima are equally bright.

Which of the above are CORRECT for diffraction at single slit?

Question 17of 30
  1. I. Each point on a wavefront acts as a source of secondary wavelets.
  2. II. The new wavefront is the forward envelope of these secondary wavelets.
  3. III. Huygens' construction explains both reflection and refraction.

Which of the above are CORRECT regarding Huygens' construction?

Question 18of 30
  1. I. Bright fringes in YDSE occur where the path difference is an integer multiple of the wavelength.
  2. II. Dark fringes occur where the path difference is an odd multiple of \(\lambda/2\).

Which of the above are CORRECT regarding interference of light?

Question 19of 30

Match each item in List I with its corresponding entry in List II:

List IList II
(i) YDSE fringe width(P) \(\dfrac{\lambda D}{d}\)
(ii) Maxima condition(Q) \(\Delta = n\lambda\)
(iii) Minima condition(R) \(\Delta = (2n-1)\dfrac{\lambda}{2}\)
(iv) Position of the \(n\)th bright fringe(S) \(\dfrac{n\lambda D}{d}\)
Question 20of 30

Match each situation in List I with the wavefront it gives in List II:

List IList II
(i) Waves from a point source spreading uniformly in all directions(P) A plane wavefront, tilted relative to the incident one
(ii) A small portion of a spherical wavefront far from its source(Q) A spherical wavefront converging to the focus
(iii) A plane wave after passing through a thin convex lens(R) A diverging spherical wavefront
(iv) A plane wave after passing through a thin prism(S) An approximately plane wavefront
Question 21of 30

Match each item in List I with its corresponding entry in List II:

List IList II
(i) Coherent sources(P) Constant phase difference
(ii) Incoherent sources(Q) No interference pattern
(iii) Sustained interference(R) Need monochromatic source
(iv) Diffraction(S) Bending around obstacle
Question 22of 30

In YDSE with \(\lambda = 600\ \text{nm}\), \(d = 0.5\ \text{mm}\), \(D = 1.5\ \text{m}\), the fringe width is:

Question 23of 30

In YDSE, slit separation \(d = 0.4\ \text{mm}\) and screen distance \(D = 2\ \text{m}\). If the 4th bright fringe is at \(y = 8\ \text{mm}\) from the central fringe, the wavelength of light used is:

Question 24of 30

In YDSE the whole apparatus is immersed in water of refractive index \(\dfrac{4}{3}\). If the fringe width in air is \(1.2\ \text{mm}\), the fringe width in water is:

Question 25of 30

In the intensity pattern of Young's double-slit experiment, the central bright fringe corresponds to:

Question 26of 30

A wavefront is refracted at the surface of a denser medium, and the refracted ray bends towards the normal. This is because:

Case study

In Young's double slit experiment, two slits separated by distance \(d\) are illuminated by monochromatic light of wavelength \(\lambda\). The interference pattern is observed on a screen at distance \(D\) from the plane of the slits. Use this configuration to answer the following questions about fringe positions, fringe width, and the intensity at points on the screen.

Question 27of 30

Based on the passage, the angular position of the first dark fringe is:

Question 28of 30

Based on the passage, the position of the 3rd bright fringe from the center is:

Question 29of 30

Based on the passage, if \(D\) is doubled, the fringe width:

Question 30of 30

Based on the passage, each slit alone would give intensity \(I_{0}\) on the screen. At a point a quarter of a fringe width, \(\dfrac{\lambda D}{4d}\), from the centre of the central bright fringe, the resultant intensity is:

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